Awindow air conditioner unit is placed on a laboratory bench and tested in cooling mode using 750 w of electric power with a cop of 1.75. what is the cooling power capacity and what is the net effect on the laboratory?

Q=1312.5 W

Explanation:

Given that

Cooling load or power input = 750 W

COP=1.75

We know that COP can be given as

COP is the ratio of cooling effect to the input power .

Lets take cooling effect is Q.So now by using COP formula

COP=Q/750

1.75=Q/750

Q=1312.5 W

So the cooling effect produce by air conditioning will be 1312.5 W.

The net effect on laboratory,the laboratory temperature will reduce.

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