The pulley has mass 12.0 kg, outer radius ro=250 mm, inner radius ri=200 mm, and radius of gyration ko=231 mm. cylinder a weighs 71.0 n. assume there is no friction between the pulley and its axle and that the rope is massless. at the instant when ω=69.0 rad/s clockwise, what is the kinetic energy of the system?

2213.7 J

Explanation:

The total kinetic energy is the sum of the kinetic energies of the pulley and the weight.

The kinetic energy of the weight is:

Ew = 1/2 * m * v^2

The mass is:

m = P / g = 71 / 9.81 = 7.24 kg

We need its speed, this is:

w * Ri = 69 * 0.2 = 13.8 m/s

So:

Ew = 1/2 *7.24 * 13.8^2 = 689.4 J

The kinetic energy of the pulley is:

Ep = 1/2 * J * w^2

The polar moment is

J = m * k0^2

Then

Ep = 1/2 * m * k0^2 * w^2

Ep = 1/2 * 12 * 0.231^2 * 69^2 = 1524.3 J

So, the kinetic energy is

689.4 + 1524.3 = 2213.7 J

the equation above shows how temperature f, measured in degrees fahrenheit, relates to a temperature c, measured in degrees celsius. based on the equation, which of the following must be true?

a temperature increase of 1 degree fahrenheit is equivalent to a temperature increase of

5

9

degree celsius.

a temperature increase of 1 degree celsius is equivalent to a temperature increase of 1.8 degrees fahrenheit.

a temperature increase of

5

9

degree fahrenheit is equivalent to a temperature increase of 1 degree celsius.

a) i only

b) ii only

c) iii only

d) i and ii only