S1.1 the acre-foot. hydraulic engineers in the united states often use, as a unit of volume of water, the acre-foot, defined as the volume of water that will cover 1 acre of land to a depth of 1 ft. a severe thunderstorm dumped 2.0 in. of rain in 30 minutes on a town of area 26 km2. what volume of water, in acre-feet, fell on the town? s1.2 the thunderstorm. what mass of water fell on the town in s1.1the acre-foot during the thunderstorm? one cubic meter of water has a mass of 103kg.

1072 acre foot

1331424000 kg

Explanation:

1 feet has 12 inches, so 2 in is 0.167 feet.

1 km^2 has 1 million m^2.

1 acre is 4074 m^2.

So, 1 km is 247 acres.

Then 26 km^2 is 6422 acres.

So, the volume of water is

6422 * 0.167 = 1072 acre-foot

Since one cubic meter of water has 1000 kg

One inch is 25.4 mm = 0.0254 m

One feet is 12 * 0.0254 = 0.3048 m

An acre-feet has a volume of

4074*0.3048 = 1242 m^3

And that is a mass of water of

1242 * 1000 = 1242000 kg/acre-feet

Therefore the mass of rainwater in the town is of

1072 * 1242000 = 1331424000 kg = 1331424 tons

answer:

the average distance would be 20ly

Explanation:

100,000ly times 5,000ly=20ly