A5 cm diameter iron ball at 80°c is dropped into an insulated tank that contains 0.5 m^3 of liquid water at 25°c. determine the temperature when thermal equilibrium is reached.

T= 25.0061 °C

Explanation:

Given that

For iron ball:

 d=5 cm

We know that for iron

So the mass of iron

Now by putting the values

m=0.51 kg

Foe water:

m=1000 x 0.5 kg

m=500 kg

So

heat loss by iron ball = heat gain by water

Lets take T is the final temperature

0.51 x 0.46 (80 -T) = 500 x 4.187 x (T-25)

T= 25.0061 °C

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