A6kg robot is required to climb a 45 degree incline. the wheel radius is 20mm, what torque is required to drive the robot at a constant rate? the robot must accelerate at up to 10 mm/s^2. what torque is required?

Given:

mass of robot, m = 6 kg

radius of the wheel, r = 20 mm = 0.02 m

acceleration, a = 10

acceleration due to gravity, g = 9.8

inclination,

Solution:

Refer to fig 1

Force is given by:

F = mgsin

Torque is given by:

Torque,                  

Refer to fig 2.

Provided the acceleration of the wheel, the Force and torque is now:

Force, F =  mgsin

Torque,

answer:

50 vo; ts

explanation: