The acceleration of a point is given. a = 20 t m/s2 when t=0, s = 50 m and v = -8 m/s. what are the position and velocity of the particle at t = 3 s?

v=82 m/s

s=116m

Explanation:

a=20t

using condition given at t=0

c=-8

now equation becomes

v=10t²-8

v at t= 3s  v=82 m/s

again

now using condition given s=50 at t=0

b=50

now equation becomes

calculating s at t=3s

s=116m

answer:

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