An indirect contact heat exchanger operating at steady state contains a shell with a single tube through it. the fluid flowing through the tube enters at 1kg/s with and enthalpy of 100kj/kg. it exits with an enthalpy of 500kj/kg. the fluid flowing through the shell enters with a mass flow rate of 4kg/s and an enthalpy of 1000kj/kg. determine the enthalpy at the exit of the shell.

900 KJ/kg

Explanation:

Given data

mass flow rate of fluid through tube is=1 kg/s

Initial enthalpy of fluid through tube=100 KJ/kg

Final enthalpy of fluid through tube=500KJ/kg

mass flow rate of fluid through shell is=4 kg/s

Initial enthalpy of fluid through shell=1000 KJ/kg

Final enthalpy of fluid through shell=

since heat lost by Shell fluid is equal to heat gain by Tube fluid  

heat lost by Shell fluid=

Heat gain by tube Fluid=

Equating both heats

=

=900 KJ/kg

sorry what a asnns

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