Aflat rectangular door in a mine is submerged froa one side in vater. the door dimensions are 2 n high, 1 n vide and the vater level is 1,5 m higher than the top of the door. the door has two hinges on the vertical edge, 160 mm from each corner and a sliding bolt on the other side in the niddle. calculate the forces on the hinges and sliding bolt. hint: consider the door from a side view and from a plaa vies respectively and take moments about a point each time.)

Force on the bolt = 24.525 kN

Force on the 1st hinge = 8.35 kN

Force on the 2nd hinge = 16.17 kN

Explanation:

Given:

height = 2 m

width =1 m

depth of the door from the water surface = 1.5 m

Therefore,

=1.5+1 = 2.5 m

Hydrostatic force acting on the door is

         = 49050 N

         = 49.05 kN

Now finding the Moment of inertia of the door about x axis

               = 0.67

Now location of force,

             = 2.634

Therefore, calculating the unknown forces

 ------------------(1)

Now since

∴

         -----------------------(2)

From (1) and (2), we get

                = 24.525 kN

This is the force on the Sliding bolt

Taking

=8.35 kN

This is the reaction force on the 1st hinge.

Now from (1), we get

=16.17 kN

This is the force on the 2nd hinge.

i mean i gues

explanation:

answer:

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explanation: