The gas expanding in the combustion space of a reciprocating engine has an initial pressure of 5 mpa and an initial temperature of 1623°c. the initial volume is 0.05 m^3 and the gas expands through a volume ratio of 20 according to the law pv^1.25 = constant. calculate: a) work transfer b) heat transfer

a). Work transfer = 527.2 kJ

b). Heat Transfer = 197.7 kJ

Explanation:

Given:

= 5 Mpa

= 1623°C

                       = 1896 K

= 0.05

Also given

Therefore, = 1  

R = 0.27 kJ / kg-K

= 0.8 kJ / kg-K

Also given :

   Therefore, =

                      = 0.1182 MPa

a). Work transfer, δW =

                              = 527200 J

                             = 527.200 kJ

b). From 1st law of thermodynamics,

Heat transfer, δQ = ΔU+δW

   =

  =

  =

  = 197.7 kJ

answer:

i lost in getting someone back.

i learned that people are really two-faced and no matter how angelic someone appears they always have a devil side and that you cant trust anyone anymore no matter how dear they are to you.

if your wondering who it waz it waz mah still miss her tho

~batmans wife dun dun

answer:

1.3 + 20

explanation:

20.1.3