Need with my java programming assignment. 10 points to whoever can answer them ! 1. which of the following is the java comparison operator that means "not equal to"? a. < = b. -= c. < > d. = 2. if x is an int with a value of 5, which of the following expressions evaluates to true? a. x > 5 b. x < = 5 c. x ! = 5 d. x < 5 3. if x is an int variable, which of the following is not a boolean expression? a. x == 9 b. x -= 3 c. x ! = 2 d. x < 0 4. if num is an int, which expression always evaluates to true if num holds an odd number? a. num % 2 == 0 b. num % 2 < 0 c. num % 2 == 1 d. num / 2 == 1

You have inserted new slides based on a word outline. how do you format these new slides to match the powerpoint presentation formatting? a. select all slides in the presentation and click format on the home tab. b. select the new slides and click reset on the home tab. c. select all slides in the presentation and click reset on the home tab. d. select the new slides and click format on the home tab.

Singing in the rain: this first part of the film shows the early history of motion picture. how accurate do you think the portrayal of the early motion picture industry is? why? is historical accuracy important in films and theater productions? explain.

When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?