Challenge 3 print("The area is ", area)
width = input("Please enter a width")
• asks the user to input the
width of a rectangle
• asks the user to input height of
a rectangle
calculates the area
outputs the result
area = width * height
width = int(width)
.Put the statements in order to solve
the challenge
height = input("Please enter a height")
height = int(height)

While inserting images, the picture command is usually used to insert photos from a digital camera, and the clip art command is usually used to a.edit the sizes and other characteristics of photos that have been inserted. b.take a screenshot of an image and copy it to the clipboard for pasting. c.search for drawings or other images from a library of prepared pictures. d.make illustrations using lines and shapes that are easy to manipulate.

Universal windows platform is designed for which windows 10 version?

The idea that, for each pair of devices v and w, there’s a strict dichotomy between being “in range” or “out of range” is a simplified abstraction. more accurately, there’s a power decay function f (·) that specifies, for a pair of devices at distance δ, the signal strength f(δ) that they’ll be able to achieve on their wireless connection. (we’ll assume that f (δ) decreases with increasing δ.) we might want to build this into our notion of back-up sets as follows: among the k devices in the back-up set of v, there should be at least one that can be reached with very high signal strength, at least one other that can be reached with moderately high signal strength, and so forth. more concretely, we have values p1 ≥ p2 ≥ . . ≥ pk, so that if the back-up set for v consists of devices at distances d1≤d2≤≤dk,thenweshouldhavef(dj)≥pj foreachj. give an algorithm that determines whether it is possible to choose a back-up set for each device subject to this more detailed condition, still requiring that no device should appear in the back-up set of more than b other devices. again, the algorithm should output the back-up sets themselves, provided they can be found.\