Given that n refers to a positive int use a while loop to compute the sum of the cubes of the first n counting numbers, and associate this value with total. Use no variables other than n, k, and total in python

The program in Python is as follows:

n = int(input("n:"))

total = 0

for k in range(1,n+1):

   total+=k**3

print(total)

Explanation:

This gets input for n

n = int(input("n:"))

This initializes total to 0

total = 0

This iterates from 1 to n

for k in range(1,n+1):

This adds up the cube of each digit

   total+=k**3

This prints the calculated total

print(total)

i think the answer is b.

explanation:

d. long term memory