Find the summation of even number between (2,n)​

The program in python is as follows:

n = int(input("n: "))

sum = 0

for i in range(2,n+1):

   if i%2 == 0:

       sum+=i

print(sum)

Explanation:

This gets input n

n = int(input("n: "))

This initializes sum to 0

sum = 0

This iterates through n

for i in range(2,n+1):

This checks if current digit is even

   if i%2 == 0:

If yes, take the sum of the digit

       sum+=i

Print the calculated even sum

print(sum)

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