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Fast sportcars the top speeds of sportscars, given in miles per hour, are: 155 mph bmw m5 217 mph lamborghini aventador spyder 205 mph ferrari 488 205 mph nissan gtr 197 mph chevrolet corvette stingray zr1 258 mph bugatti veyron supersport 195 mph dodge viper 270 mph hennessey venom 155 mph bmw m3 195 mph mercedes sl given: topspeeds=[155; 217; 205; 205; 197; 258; 195; 270; 155; 195]; carnames=string(["bmw m5" "lamborghini aventador spyder" "ferrari 488" "nissan gtr" "chevrolet corvette stingray zr1" "bugatti veyron supersport" "dodge viper" "hennessey venom" "bmw m3" "mercedes sl"]); the variable is a rectangular array. write a function called selectcars to identify cars with the top speed within a given range, and display the identified names. the selected cars speed will be in a range given by lowerbound < speed < upperbound. inputs to the function selectcars are: a column array os all car top speeds named topspeeds, the corresponding chara

4.11 painting a wall (1) prompt the user to input integers for a wall's height and width. calculate and output the wall's area (integer). note that in this case there is a new line after each prompt. (submit for 1 point). enter wall height (feet): 11 enter wall width (feet): 15 wall area: 165 square feet (2) extend to also calculate and output the amount of paint in gallons needed to paint the wall (floating point). assume a gallon of paint covers 350 square feet. store this value in a variable. output the amount of paint needed using the %f conversion specifier. (submit for 2 points, so 3 points total). enter wall height (feet): 11 enter wall width (feet): 15 wall area: 165 square feet paint needed: 0.471429 gallons (3) extend to also calculate and output the number of 1 gallon cans needed to paint the wall. hint: use a math function to round up to the nearest gallon. (submit for 2 points, so 5 points total). enter wall height (feet): 11 enter wall width (feet): 15 wall area: 165 square feet paint needed: 0.471429 gallons

Write a program called assignment3 (saved in a file assignment3.java) that computes the greatest common divisor of two given integers. one of the oldest numerical algorithms was described by the greek mathematician, euclid, in 300 b.c. it is a simple but very e↵ective algorithm that computes the greatest common divisor of two given integers. for instance, given integers 24 and 18, the greatest common divisor is 6, because 6 is the largest integer that divides evenly into both 24 and 18. we will denote the greatest common divisor of x and y as gcd(x, y). the algorithm is based on the clever idea that the gcd(x, y) = gcd(x ! y, y) if x > = y and gcd(x, y) = gcd(x, y ! x) if x < y. the algorithm consists of a series of steps (loop iterations) where the “larger” integer is replaced by the di↵erence of the larger and smaller integer. this continues until the two values are equal. that is then the gcd.