Consider a disk with an average seek time of 8 msec and a worst-case seek time of 16 msec, a rotational rate of 7200 rpm (revolutions per minute), and 548548 bytes per track. Given a block size of k bytes, determine the time taken (in msec) in the worst case to read a single block. You can leave your answer in terms of k. You can assume all tracks store the same number of bytes, and that the k bytes here all lie on the same track. There is no need to simplify the formula. It is more important to explain how you got to your math.

Given int variables k and total that have already been declared, use a while loop to compute the sum of the squares of the first 50 counting numbers, and store this value in total. thus your code should put 11 + 22 + 33 + + 4949 + 50*50 into total. use no variables other than k and total.

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The use of phrases, fragments, and punctuation can influence the mood of a passage; keeping this in mind, how would you describe the mood of the followingpassage? "fog on the essex marshes, fog on the kentish heights, fog creeping into the cabooses of collier-brigs; fog lying out on the yards, and hovering in the riggingof great ships; fog drooping on the gunwales of barges and small boats. fog in the eyes and throats of ancient greenwich pensioners, wheezing by thefiresides of their wards; fog in the stem and bowl of the afternoon pipe of the wrathful skipper; fog cruelly pinching the toes and fingers of his shivering little'prentice boy on deck." (5 points)