Define a function is_prime that receives an integer argument and returns true if the argument is a prime number and otherwise returns false. (an integer is prime if it is greater than 1 and cannot be divided evenly [with no remainder] other than by itself and one. for example, 15 is not prime because it can be divided by 3 or 5 with no remainder. 13 is prime because only 1 and 13 divide it with no remainder.) this function may be written with a for loop, a while loop or using recursion.

Study the for statement carefully!

```
#!/usr/local/bin/python3

import sys, math

def is_prime( number ):
    if( number % 2 == 0 ):
        return False
    else:
        for i in range( 3, int( math.sqrt( number ) ) + 1, 2 ):
            if( number % i == 0 ):
                return False
        return True

if( __name__ == "__main__" ):
    if( len( sys.argv ) != 2 ):
        sys.stderr.write( "\nusage: " + sys.argv[ 0 ] + " <integer>\n\n" )
        exit( 127 )

    print( is_prime( int( sys.argv[ 1 ] ) ) )
```

4because of my mind tells me to pick 4

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