Please help me I need to complete this i will give brainliest Consider the following code segment.

for (int outer = 0; outer < n; outer++)
{
for (int inner = 0; inner <= outer; inner++)
{
System. out. print(outer + " ");
}
}
If n has been declared as an integer with the value 4, what is printed as a result of executing the
code segment?

Group of answer choices

0 0 1 0 1 2 0 1 2 3

0 1 2 2 3 3 3

0 1 1 2 2 2 3 3 3 3

0 1 2 3

0 0 1 0 1 2

Which of the following commands is more recommended while creating a bot?

Which of these is a benefit of using objects in a powerpoint presentation? a. collaborators can create the external files while you create and edit the slide show. b. you can easily change the theme and design of the presentation. c. you can have older data in the source file while having up-to-date data in the presentation. d. collaborators can easily share the presentation.

The idea that, for each pair of devices v and w, there’s a strict dichotomy between being “in range” or “out of range” is a simplified abstraction. more accurately, there’s a power decay function f (·) that specifies, for a pair of devices at distance δ, the signal strength f(δ) that they’ll be able to achieve on their wireless connection. (we’ll assume that f (δ) decreases with increasing δ.) we might want to build this into our notion of back-up sets as follows: among the k devices in the back-up set of v, there should be at least one that can be reached with very high signal strength, at least one other that can be reached with moderately high signal strength, and so forth. more concretely, we have values p1 ≥ p2 ≥ . . ≥ pk, so that if the back-up set for v consists of devices at distances d1≤d2≤≤dk,thenweshouldhavef(dj)≥pj foreachj. give an algorithm that determines whether it is possible to choose a back-up set for each device subject to this more detailed condition, still requiring that no device should appear in the back-up set of more than b other devices. again, the algorithm should output the back-up sets themselves, provided they can be found.\