Print person1's kids, call the incNumKids() method, and print again, outputting text as below. End each line with a newline. Sample output for below program with input 3:
Kids: 3
New baby, kids now: 4
// Code from file PersonInfo. java
public class PersonInfo {
private int numKids;

public void setNumKids(int setPersonsKids) {
numKids = setPersonsKids;
}

public void incNumKids() {
numKids = numKids + 1;
}

public int getNumKids() {
return numKids;
}
}
// end

// Code from file CallPersonInfo. java
import java. util. Scanner;

public class CallPersonInfo {
public static void main(String [] args) {
Scanner scnr = new Scanner(System. in);
PersonInfo person1 = new PersonInfo();
int personsKid;

personsKid = scnr. nextInt();

person1.setNumKids(personsKid);

/* Your solution goes here */

}
}
// end

Explanation:

The following code was written in Java and modifies the code so that for the given input such as 3 it outputs the exact information shown in the sample output.

import java.util.Scanner;

class CallPersonInfo {

   public static void main(String [] args) {

       Scanner scnr = new Scanner(System.in);

       PersonInfo person1 = new PersonInfo();

       int personsKid;

       System.out.println("How many kids do you have:");

       personsKid = scnr.nextInt();

       person1.setNumKids(personsKid);

       /* Your solution goes here */

       System.out.println("Kids: " + person1.getNumKids());

       person1.incNumKids();

       System.out.println("New Baby, kids now: " + person1.getNumKids());

   }

}

class PersonInfo {

   private int numKids;

   public void setNumKids(int setPersonsKids) {

       numKids = setPersonsKids;

   }

   public void incNumKids() {

       numKids = numKids + 1;

   }

   public int getNumKids() {

       return numKids;

   }

}

answer: a, c

divide any of the y values by x values and you will always get 3 is the most simple way i can put it for you.

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.