Задача в том, чтобы считать весь текст и разбить его на части, каждая из которых по возможности не
превышала бы 1000 символов, при этом разбивать абзацы (строки) на
части нельзя.

Представим, что мы считали текст, который состоит из строк следующей
длины:
100
500
300
600
1100
50
Тогда мы должны были бы его разбить на 4 части:
1 из первых трех строк (100+500+300)
2 из четвертой строки (600)
3 из пятой строки (1100)
4 из шестой строки (50).

You should try to photograph people on bright sunny days because the light will be best a) true b) false

Creating "smart interfaces" in all sectors of industry, government, and the public arena is one of the fastest growing hct areas. these interfaces model, interpret, and analyze such human characteristics as speech, gesture, and vision. the field of biometrics, in which humans authenticate themselves to machines, is an area of considerable interest to hct practitioners. fingerprint scans are one of the most frequently used biometric options, and this article, biometric student identification: practical solutions for accountability & security in schools, makes a case for the implementation of fingerprint scans in schools. critique the article, and answer the following questions: according to the author, what are the main benefits of adopting fingerprint scans in schools for student identification? according to the author, what are the main drawbacks of adopting fingerprint scans in schools for student identification? do you agree with the author's assessment of the pl

Fill in the following program so that it will correctly calculate the price of the orange juice the user is buying based on the buy one get one sale.#include //main functionint main() { int cartons; float price, total; //prompt user for input information printf("what is the cost of one container of oj in dollars? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & price); printf("how many containers are you buying? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & cartons); if ( [ select ] ["cartons / 2", "cartons % 1", "cartons % 2", "cartons % price", "cartons / price", "cartons / total"] [ select ] ["=", "==", "! =", "< =", "> =", "< "] 0) total = [ select ] ["price * cartons", "cartons * price / 2 + price", "(cartons / 2) * price", "cartons / (2.0 * price)", "(cartons / 2.0) * price + price", "((cartons / 2) * price) + price"] ; else total = ((cartons / 2) * price) + price; printf("the total cost is $%.2f.\n", total); return 0; }