)Assume passwords are limited to the use of the 95 printable ASCII characters and that all passwords are 10 characters in length. Assume a password cracker with an encryption rate of 6.4 million encryptions per second. How long will it take to test exhaustively all possible passwords on a UNIX system

296653 years

Explanation:

The length of password = 10

To get possible password:

95 printable password raised to power 10

= 95¹⁰

Then we calculate time it would take to break password

95¹⁰/6.4million

95¹⁰/6400000

= 9355264675599.67 seconds

From here we get minutes it would take. 60 secs = 1 min

= 9355264675599.67/60

= 155921077927 minutes

From here we get number of hours it would take 1 hr = 60 mins

155921077927/60

= 2598684632 hours

From here we calculate number of days it would take. 24 hrs = 1 day

2598684632/24

= 108278526 days

From here we calculate number of years it would take. 365 days = 1 ye

= 108278526/365

= 296653 years

It would take this number of years to test all possible passwords

answeruse the nslookup utility;