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Modified Binary Search Modify the binary search algorithm so that it returns an array of length 2 with the lowest index and highest index of those element(s) that equal the searched value. For example, when searching for 3, if the array contains the values 1 1 3 3 3 4 5 5, the algorithm should return [2, 4]. If the value is not found, return an array of length 1 containing the index at which the value should be inserted. Your implementation should have O(log n) running time even if most elements of the array have the same value. Add appropriate Junit tests.

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Create a function (prob3_6) that will do the following: input a positive scalar integer x. if x is odd, multiply it by 3 and add 1. if the given x is even, divide it by 2. repeat this rule on the new value until you get 1, if ever. your program will output how many operations it had to perform to get to 1 and the largest number along the way. for example, start with the number 3: because 3 is odd, we multiply by 3 and add 1 giving us 10. 10 is even so we divide it by 2, giving us 5. 5 is odd so we multiply by 3 and add one, giving us 16. we divide 16 (even) by two giving 8. we divide 8 (even) by two giving 4. we divide 4 (even) by two giving 2. we divide 2 (even) by 2 to give us 1. once we have one, we stop. this example took seven operations to get to one. the largest number we had along the way was 16. every value of n that anyone has ever checked eventually leads to 1, but it is an open mathematical problem (known as the collatz conjectureopens in new tab) whether every value of n eventually leads to 1. your program should include a while loop and an if-statement.
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Modified Binary Search Modify the binary search algorithm so that it returns an array of length 2 w...
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