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Implement the function permutations() that takes a list lst as input and returns a list of all permutations of lst (so the returned value is a list of lists). Do this recursively as follows: If the input list lst is of size 1 or 0, just return a list containing list lst. Otherwise, make a recursive call on the sublist l[1:] to obtain the list of all permutations of all elements of lst except the first element l[0]. Then, for each such permutation (i. e., list) perm, generate permutations of lst by inserting lst[0] into all possible positions of perm. >>> permutations([1, 2])

[[1, 2], [2, 1]]

>>> permutations([1, 2, 3])

[[1, 2, 3], [2, 1, 3], [2, 3, 1], [1, 3, 2], [3, 1, 2], [3, 2, 1]]

>>> permutations([1, 2, 3, 4])

[[1, 2, 3, 4], [2, 1, 3, 4], [2, 3, 1, 4], [2, 3, 4, 1],

[1, 3, 2, 4], [3, 1, 2, 4], [3, 2, 1, 4], [3, 2, 4, 1],

[1, 3, 4, 2], [3, 1, 4, 2], [3, 4, 1, 2], [3, 4, 2, 1],

[1, 2, 4, 3], [2, 1, 4, 3], [2, 4, 1, 3], [2, 4, 3, 1],

[1, 4, 2, 3], [4, 1, 2, 3], [4, 2, 1, 3], [4, 2, 3, 1],

[1, 4, 3, 2], [4, 1, 3, 2], [4, 3, 1, 2], [4, 3, 2, 1]]

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