Look at (d), is it accurate? ​

Janice recently received her college degree and is looking for a job. she is worried that since she just finished school, she will be required to repay her perkins and direct subsidized loans immediately. janice pulls out the paperwork she signed and reviews it again for repayment information. after reading all of the information, janice discovers that

Multiple choice project create a program with two multiple choice questions. 1. users have two attempts only, show attempt number each time. hint: while loop with break control. (20%) 2. only one correct answer for each question, use switch case for each question. (20%) 3. show total score after the two questions are answered. hint: . (20%) 4. user have options to answer the two questions again if first attempt score is not 100%. hint: if statment. (20%) 5. use string method .toupper() to allow users to enter with lowercase or uppercase letters. (20%) 1. where is the capital of the state of florida? a. orlando b. tallahassee c. miami d. tampa b 2. where is walt disney world park located in florida? a. orlando b. tallahassee c. miami d. tampa a

The idea that, for each pair of devices v and w, there’s a strict dichotomy between being “in range” or “out of range” is a simplified abstraction. more accurately, there’s a power decay function f (·) that specifies, for a pair of devices at distance δ, the signal strength f(δ) that they’ll be able to achieve on their wireless connection. (we’ll assume that f (δ) decreases with increasing δ.) we might want to build this into our notion of back-up sets as follows: among the k devices in the back-up set of v, there should be at least one that can be reached with very high signal strength, at least one other that can be reached with moderately high signal strength, and so forth. more concretely, we have values p1 ≥ p2 ≥ . . ≥ pk, so that if the back-up set for v consists of devices at distances d1≤d2≤≤dk,thenweshouldhavef(dj)≥pj foreachj. give an algorithm that determines whether it is possible to choose a back-up set for each device subject to this more detailed condition, still requiring that no device should appear in the back-up set of more than b other devices. again, the algorithm should output the back-up sets themselves, provided they can be found.\