What is the most commonly used tab in the Filter dialog box?
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Computers and Technology, 21.01.2021 03:10 kymberlyasher
What is the most commonly used tab in the Filter dialog box?
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Computers and Technology, 22.06.2019 19:40
Solve the following javafx application: write a javafx application that analyzes a word. the user would type the word in a text field, and the application provides three buttons for the following: - one button, when clicked, displays the length of the word.- another button, when clicked, displays the number of vowels in the word.- another button, when clicked, displays the number of uppercase letters in the word(use the gridpane or hbox and vbox to organize the gui controls).
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Computers and Technology, 22.06.2019 20:00
What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i.e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }
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Computers and Technology, 23.06.2019 18:00
Apunishment or the threat of punishment used to enforce conformity. select the best answer from the choices provided t f
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Computers and Technology, 24.06.2019 11:20
Print "censored" if userinput contains the word "darn", else print userinput. end with newline. ex: if userinput is "that darn cat.", then output is: censoredex: if userinput is "dang, that was scary! ", then output is: dang, that was scary! note: if the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "program end never reached." the system doesn't print the test case that caused the reported message.#include #include using namespace std; int main() {string userinput; getline(cin, userinput); int ispresent = userinput.find("darn"); if (ispresent > 0){cout < < "censored" < < endl; /* your solution goes here */return 0; }
Answers: 3
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