Write a program that takes a set of numbers and determines which is the smallest. Ask the user for the following information, in this order: A terminating value (real number). The user will enter this value again later, to indicate that he or she is finished providing input. A sequence of real numbers. Keep asking for numbers until the terminating value is entered.

This solution is implemented in C++:

#include<iostream>

#include<bits/stdc++.h>

using namespace std;

int main(){

double termnum;

cout<<"Terminating number: ";

cin>>termnum;

double num;

vector<double>numbers;

cout<<"Number: ";

cin>>num;

while(num!=termnum){

numbers.push_back(num);

cout<<"Number: ";

cin>>num;

}

double smallest = numbers.at(0);

for(double x:numbers){

 if(x < smallest){

 smallest = x;

 }

}

cout<<"The smallest is "<<smallest;

return 0;  

}

Explanation:

This declares the terminating variable as double

double termnum;

The next italicized lines prompts user for terminating value

cout<<"Terminating number: ";  

cin>>termnum;

This declares the user input variable as double  

double num;

This declares vector of numbers as double

vector<double>numbers;

The next italicized lines prompts user for number

cout<<"Number: ";

cin>>num;

The following iteration is repeated until the terminating value equals the number supplies by the user

while(num!=termnum){

This pushes the number to a vector

numbers.push_back(num);

The italicized lines prompts user for another number

cout<<"Number: ";

cin>>num;

}

This declares and initializes variable smallest

double smallest = numbers.at(0);

The following for loop determines the smallest of the number set

for(double x:numbers){

 if(x < smallest){

 smallest = x;

 }

}

 This prints the smallest of the set

cout<<"The smallest is "<<smallest;

return 0;

Also: See attachment