EO Use the text below to answer the question.
CARDS
Light can also pass through some things. Light can easily pass through
clear objects, like glass windows. That's why you can see through clear
objects.
GAME
D &
OND
There are also some objects that let only some light pass through-stained
glass windows and sunglasses, for example. They block some light and let
other light pass through. So you can see through them, but not as well as
you can see through clear glass.
What is the question

Computer programming is one type of what career

With editing, word automatically displays a paste options button near the pasted or moved text. a. cut-and-paste b. drag-and-drop c. inline d. copy-and-carry

The idea that, for each pair of devices v and w, there’s a strict dichotomy between being “in range” or “out of range” is a simplified abstraction. more accurately, there’s a power decay function f (·) that specifies, for a pair of devices at distance δ, the signal strength f(δ) that they’ll be able to achieve on their wireless connection. (we’ll assume that f (δ) decreases with increasing δ.) we might want to build this into our notion of back-up sets as follows: among the k devices in the back-up set of v, there should be at least one that can be reached with very high signal strength, at least one other that can be reached with moderately high signal strength, and so forth. more concretely, we have values p1 ≥ p2 ≥ . . ≥ pk, so that if the back-up set for v consists of devices at distances d1≤d2≤≤dk,thenweshouldhavef(dj)≥pj foreachj. give an algorithm that determines whether it is possible to choose a back-up set for each device subject to this more detailed condition, still requiring that no device should appear in the back-up set of more than b other devices. again, the algorithm should output the back-up sets themselves, provided they can be found.\