Consider the use of 1000-bit frames on a 1-Mbps satellite channel with a 270-ms delay. What is the maximum link utilization for, a. Stop-and-wait flow control?
b. Continuous flow control with a window size of 7?
c. Continuous flow control with a window size of 127?

)a grad student comes up with the following algorithm to sort an array a[1..n] that works by first sorting the first 2/3rds of the array, then sorting the last 2/3rds of the (resulting) array, and finally sorting the first 2/3rds of the new array. 1: function g-sort(a, n) . takes as input an array of n numbers, a[1..n] 2: g-sort-recurse(a, 1, n) 3: end function 4: function g-sort-recurse(a, `, u) 5: if u ⒠` ≤ 0 then 6: return . 1 or fewer elements already sorted 7: else if u ⒠` = 1 then . 2 elements 8: if a[u] < a[`] then . swap values 9: temp ↠a[u] 10: a[u] ↠a[`] 11: a[`] ↠temp 12: end if 13: else . 3 or more elements 14: size ↠u ⒠` + 1 15: twothirds ↠d(2 ◠size)/3e 16: g-sort-recurse(a, `, ` + twothirds ⒠1) 17: g-sort-recurse(a, u ⒠twothirds + 1, u) 18: g-sort-recurse(a, `, ` + twothirds ⒠1) 19: end if 20: end function first (5 pts), prove that the algorithm correctly sorts the numbers in the array (in increasing order). after showing that it correctly sorts 1 and 2 element intervals, you may make the (incorrect) assumption that the number of elements being passed to g-sort-recurse is always a multiple of 3 to simplify the notation (and drop the floors/ceilings).

The following is an excerpt from a slide presentation. today we will inverse operations solving equations using inverse operations solving inequalities using inverse operations from which part of the presentation does the slide most likely come from? a. introduction b. outline c. body d. conclusion

3. what is the output of the following statements? temporary object1; temporary object2("rectangle", 8.5, 5); temporary object3("circle", 6, 0); temporary object4("cylinder", 6, 3.5); cout < < fixed < < showpoint < < setprecision(2); object1.print(); object2.print(); object3.print(); object4.print(); object1.set("sphere", 4.5, 0); object1.print();