If the processor has 32 address lines in its address bus; i. e. 32-bit address range, what is its address space or range; i. e. what is the smallest and largest address that can be represented

The answer is "0 to 4294967295"

Explanation:

Given bit:

32 bits

Calculating smallest and largest bits:

In any processor, it works only on the 0 and 1 bit and it also stores 0 and 1 values. so, the smallest address in bit value is= 0 and the largest bit value can be defined as follows:

largest address value in bits:

smallest address= 0

largest address = 4294967295

answerthe reference of the object;