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CHALLENGE ACTIVITY | 6.2.2: Function call in expression.
Assign to maxSum the max of (numa, numB) PLUS the max of (numy, numz). Use just one statement. Hint: Call FindMax() twice in an expression.
1. #include
2. using namespace std; passed
3.
4. double FindMax(double numi,
5. double num2) { double maxVal; emos
6.
7. // Note: if-else statements need not be understood to complete this activity
8. if (numi > num2) { // if num1 is greater than num2,
9. maxVal = num1; // then num1 is the maxVal.
10.
11. All tests passed else
12. {maxVal = num2; // Otherwise, // num2 is the maxval.
13.
14.
15. return maxVal;
16. }
17.
18. int main() {
19. double numA;
20. double numB;
21. double numY;
22. double numz;

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CHALLENGE ACTIVITY | 6.2.2: Function call in expression.
Assign to maxSum the max of (numa,...
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