On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * r^n, where n is the distance (number of keys) from that key, and r is 2^(1/12). Given an initial key frequency, output that frequency and the next 4 higher key frequencies. Ex: If the input is 440 (the A key near the middle of a piano keyboard), the output is: 440.0 466.1637615180899 493.8833012561241 523.2511306011974 554.3652619537442 Note: Use one statement to compute r = 2^(1/12) using the RaiseToPower() function. Then use that r in subsequent statements that use the formula fn = f0 * r^n with n being 1, 2, 3, and finally 4.

Following are the code to this question:

import math# import math module

def RaiseToPower():   # defining a function RaiseToPower

   r= math.pow(2,1/12)    # defining r variable that calcualte the decimal point value.

   return r # return r variable value.

f0= float(input()) #defining f0 variable that hold input frequency .

for n in range(0,5):#defining for loop to count all frequency

   fn = f * math.pow(RaiseToPower(),n)    # defining fn variable that calls method RaiseToPower and multiply the value by frequency

   print(fn,end=' ')    # use print method to prints all five frequency

Output:

440

440.0 466.1637615180899 493.8833012561241 523.2511306011974 554.3652619537443

Explanation:

Description of the above python code can be defined as follows:

its true for the one time