A baseball diamond is really a square, and the distance between consecutive bases is 90 ft. How far does a catcher have to throw the ball to get it to second base if a runner tries to steal second?

84.85ft

The line from home plate to second base forms the hypotenuse of right triangle. The two sides of the triangle are each

60ft

. Using the Pythagorean theorem, we can find the length of the hypotenuse:

602+602=c2= 3600+3600=c2= 7200

=c2√7200=84.85

Therefore, the distance that the catcher will need to throw the ball to get a runner out at second base is

84.85ft

answer; wireshark;