Assume that k corresponds to register $s0, n corresponds to register $s2 and the base of the array v is in $s1. What is the MIPS assembly code corresponding to this C segment

hello your question lacks the C segment so here is the C segment

while ( k<n )

{v[k] = v[k+1];

     k = k+1; }

Answer : while:

   bge $s0, $s2, end   # while (k < n)

   addi $t0, $s0, 1    # $t0 = k+1

   sll $t0, $t0, 2     # making k+1 indexable

   add $t0, $t0, $s1   # $t0 = &v[k+1]

   lw $t0, 0($t0)      # $t0 = v[k+1]

   sll $t1, $s0, 2     # making k indexable

   add $t1, $t1, $s1   # $t1 = &v[k]

   sw $t0, 0($t1)      # v[k] = v[k+1]

   addi $s0, $s0, 1

   j while

end:

Explanation:

The MIPS assembly code corresponding to the C segment is

while:

   bge $s0, $s2, end   # while (k < n)

   addi $t0, $s0, 1    # $t0 = k+1

   sll $t0, $t0, 2     # making k+1 indexable

   add $t0, $t0, $s1   # $t0 = &v[k+1]

   lw $t0, 0($t0)      # $t0 = v[k+1]

   sll $t1, $s0, 2     # making k indexable

   add $t1, $t1, $s1   # $t1 = &v[k]

   sw $t0, 0($t1)      # v[k] = v[k+1]

   addi $s0, $s0, 1

   j while

end:

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