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Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint: Call FindMax() twice in an expression. #include
double FindMax(double num1, double num2) {
double maxVal = 0.0;
// Note: if-else statements need not be understood to complete this activity
if (num1 > num2) { // if num1 is greater than num2,
maxVal = num1; // then num1 is the maxVal.
}
else { // Otherwise,
maxVal = num2; // num2 is the maxVal.
}
return maxVal;
}
int main(void) {
double numA = 5.0;
double numB = 10.0;
double numY = 3.0;
double numZ = 7.0;
double maxSum = 0.0;
/* Your solution goes here */
printf("maxSum is: %.2f\n", maxSum);
return 0;
}

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Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint:...
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