#Write a function called "scramble" that accepts a string #as an argument and returns a new string. The new string #should start with the last half of the original string #and end with the first half. # #If the length of the string is odd, split the string #at the floor of the length / 2 (in other words, the second #half is the longer half). # #For example: # scramble("abcd") -> "cdab" # screamble("abcde") -> "cdeab" # scramble("railroad")) -> "roadrail" # scramble("fireworks")) -> "worksfire"

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Public static int mystery(int a[], int x) {     int c = 0;     for(int i = 0; i < a.length; i++) {        if (a[i] == x) c++;     } return c; }the method counts how many times an integer shows up in an integer array.the c variable is declared in the method to keep track of how many times the certain value has shown up.the for-loop loops through the entire array.the line    if (a[i] == x) c++;   checks if each element of the array is equal to the inputted integer to check. for each number in the array that is equal to the inputted integer x, the c variable will be incremented by 1. otherwise it will do nothing.then c is returned at the end of the loop.for example, if we have, in the main method with the mystery method coded in the class:     int arraytest[] = {2, 23, 23, 23, 3};     int testme = 23;     int count = mystery(arraytest, testme);     system.out.println(count); then the print out will be    3 because there are three 23s in that array.