Write a program with a method that plays the guess a number game. The program should allow the user to pick a number between 1 and 1000 in his head. The method should guess the user's number in a minimal amount of attempts. The method should ask the user "is the number greater than or less than the number " and the program gives a particular number. The user in some way just inputs (higher or lower) or (greater than or less than). There also has to be a way for the user to say the number has just been guessed. Of course, the user cannot answer incorrectly or change the number midstream. Note - if written efficiently, the method should be able to guess any number in 10 or less attempts.

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Explanation:

That's the code and it is done with the program in c++ according to instructions given in the question using binary search. It can guess the correct number in 10 or fewer attempts and also shows the number of attempts it took to guess the number.

#include <iostream> using namespace std; int guess() { string input; int l = 1, h = 1000; int mid = (l + h) / 2, count = 0; while (1) { //count the number of attemts to guess the number ++count; //cout << count << "\n"; cout << "\n"; cout << "Is " << mid << " correct? (y/n): "; cin >> input; //if input is y print the guessed no. and return if (input == "y") { cout << mid << " guessed in " << count << " attempts!\n"; return 1; } //if input is n ask the user if it's higher or lower than current guess if (input == "n") { cout << "Is the number greater than or less than the number ? (h/l): "; cin >> input; } //if input is higher assign mid incremented by 1 to low //else decrement mid by 1 and assign to high if (input == "h") l = mid + 1; else h = mid - 1; //calculate mid again according to input by user again mid = (l + h) / 2; } } int main() { cout << "WELCOME TO THE GUESS THE NUMBER GAME!\n"; cout << "Guess any number between 1 to 1000.\n"; cout << "This game depends on user giving correct answers and not changing their number middle of game.\n"; guess(); }