Complete the AddBidirectionalEdge() method. Assume both parameters are properly null terminated "strings" and the strcmp library method can be used for comparing "strings".

class AdjacencyMatrix{
private:
int matrix[10][10]; // adjacency matrix
int index[10]; // index within "matrix" corresponding to same index in array "label"
char* label[10]; // name of each vertex in "matrix"

public:
bool AddBidirectionalEdge(char* V1, char* V2) {
// input parameters (vertex names) may or may not exist in "label"
// return true if edge successfully added, otherwise return false
}
};

1. you have a small business that is divided into 3 departments: accounting, sales, and administration. these departments have the following number of devices (computers, printers, etc.): accounting-31, sales-28, and administration-13. using a class c private network, subnet the network so that each department will have their own subnet. you must show/explain how you arrived at your conclusion and also show the following: all available device addresses for each department, the broadcast address for each department, and the network address for each department. also, determine how many "wasted" (not usable) addresses resulted from your subnetting (enumerate them).

Write a program that prints the day number of the year, given the date in the form month-day-year. for example, if the input is 1-1-2006, the day number is 1; if the input is 12-25-2006, the day number is 359. the program should check for a leap year. a year is a leap year if it is divisible by 4, but not divisible by 100. for example, 1992 and 2008 are divisible by 4, but not by 100. a year that is divisible by 100 is a leap year if it is also divisible by 400. for example, 1600 and 2000 are divisible by 400. however, 1800 is not a leap year because 1800 is not divisible by 400.

Create a string list. 2. use console.readline() to collect values of firstname, lastname, street, city, state, zip, save them to list. 3. write a simple linq statement, call method uppercasewords() to change first letter to uppercase. 4. create a foreach statment to display the information. public static string uppercasewords(string value) { char[] array = value.tochararray(); if (array.length > = 1) { if (char.islower(array[0])) { array[0] = char.toupper(array[0]); } } for (int i = 1; i < array.length; i++) { if (array[i - 1] == ' ') { if (char.islower(array[i])) { array[i] = char.toupper(array[i]); } } } return new string(array);