A large IPv4 datagram is fragmented into 4 fragments at router 1 to pass over a network with an MTU of 1500 bytes. Assume each fragment is larger than 900 bytes. Then, each fragment arrives at router 2, which wants to forward the fragments over a network with an MTU of 900 bytes to deliver to the destination.

How many fragments will arrive at the destination host?

8

Explanation:

Having in mind that all the given 4 fragments are larger than 900 bytes and smaller than 1500 bytes, this will make router 2 to fragment each fragment by router 1 into 2 fragments .

Hence, 4*2 = 8 fragments will reach at destination host.

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