Make sure to read all of these specifications carefully. Write a function, named array_shifter, that accepts an array of doubles and the array’s size as arguments. The function should create a new array that is one element larger than the argument array.

import java.util.Arrays;

public class num2 {

   public static void main(String[] args) {

//Create and initialize the first array        

double [ ]arr = {3.5, 5.6, 4.5, 6.7};

// Get the length of the array

       int n = arr.length;

      //Call the method Array Shifter inside the output statement

       System.out.println(Arrays.toString(array_shifter(arr,n)));

   }

   static double [] array_shifter(double [ ] doubleArray, int n){

       double [] narr = new double[n+1];

       //Loop through from index 1

       for(int i =0; i<narr.length-1; i++){

           narr[i] = doubleArray[i];

       }

       //Put a new element at the last index

       narr[narr.length-1] = 1.1;

       return narr;

   }

}

Explanation:

This is implemented in Java

Read detailed comments in the solution

The method array_shifter creates a new array that is one element larger than the array it received as argument and returns it

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answer6-9 screws;