In this problem, you will fill in the code for a function count_digits(val) that takes a positive integer, val, and returns a list containing the count of the number of times that each digit 0 - 9 appears in val. Type the provided code into IDLE (or whatever Python IDE you are using). You will fill in the code where specified in the count_digits function. The function contains the line of code count_lst

def count_digits(val):

   count_lst = [0] * 10

   val = str(val)

   for digit in val:

       if digit == "0":

         count_lst[0] += 1

       elif digit == "1":

         count_lst[1] += 1

       elif digit == "2":

         count_lst[2] += 1

       elif digit == "3":

         count_lst[3] += 1

       elif digit == "4":

         count_lst[4] += 1

       elif digit == "5":

         count_lst[5] += 1

       elif digit == "6":

         count_lst[6] += 1

       elif digit == "7":

         count_lst[7] += 1

       elif digit == "8":

         count_lst[8] += 1

       elif digit == "9":

         count_lst[9] += 1

   return count_lst

Explanation:

Create a function called count_digits that takes one integer parameter, val

Initialize a count_list that will hold the counts for the digits in the val

Convert val to string

Initialize a for loop that iterates through the val

Inside the loop, check each digit in val and increment its corresponding position in the count_list

When the loop is done, return the count_list

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-ttl