ConsonantCount (s2) Write the function consonantCountthat counts how many times a consonant (either lowercase or uppercase) occurs in a string. It takes a string sas input and returnsan integer, the number of consonants in the string. For this question, yand Yare not consonants. Please use a for loop to do the computation. Please do not use a brute force solution (comparing against one consonant at a time): it will not receive credit.

public static int consonantCount(String str){

       int numOfConsonants =0;

       int numOfVowels =0;

       String word = str.toLowerCase();

       for(int i=0; i< word.length(); i++){

           if(word.charAt(i)=='a'||word.charAt(i)=='i'||word.charAt(i)=='o'

                   ||word.charAt(i)=='e'||word.charAt(i)=='u'||word.charAt(i)=='y'){

              numOfVowels++;

           }

       }

       numOfConsonants = (word.length()-numOfVowels);

       return numOfConsonants;

   }

Explanation:

Using Java programming Language

import java.util.Scanner;

public class num2 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter a String");

       String a = in.nextLine();

       String cleanText = a.replaceAll("[^a-zA-Z0-9]", "");

       System.out.println("The number of consonants in the word are "+consonantCount(cleanText));

   }

   public static int consonantCount(String str){

       int numOfConsonants =0;

       int numOfVowels =0;

       String word = str.toLowerCase();

       for(int i=0; i< word.length(); i++){

           if(word.charAt(i)=='a'||word.charAt(i)=='i'||word.charAt(i)=='o'

                   ||word.charAt(i)=='e'||word.charAt(i)=='u'||word.charAt(i)=='y'){

              numOfVowels++;

           }

       }

       numOfConsonants = (word.length()-numOfVowels);

       return numOfConsonants;

   }

}

they really not common the os x is just a better version of the os like in iphone theirs xr and their xs