Write a program that reads the number of years ago that a dinosaur lived and then compute the equivalent number of months, days, and seconds ago. Use 365.25 days per year. Test your program with a triceratops that lived 145 million years ago and a brontosaurus that lived 182 million years ago. (Hint: Use type double for all variables.) Note: Include functions in your program

#include <iostream>

using namespace std;

int main()

{

double year;

cout<<"Enter the number of years"<<endl;

cin>>year;

int month=year*12;

int days=year*365;

int hrs= year*(365*12);

int mins= year*(365*12*60);

int secs= year*(365*12*60*60);

cout<<"Months "<<month<<endl;

cout<<"Days "<<days<<endl;

cout<<"Hours "<<hrs<<endl;

cout<<"Minutes "<<mins<<endl;

cout<<"Secs "<<secs<<endl;

cin>>month;

}

Explanation:

the answer to your question would be something called hertz. the unit of measurement called a hertz, which is one cycle per second, is used to measure clock speed. within one cycle, your computer processes, refreshes, or updates itself to the changes that it is going through. in the case of computer clock speed, one hertz equals one tick per second. the clock speed of computers is usually measured in megahertz (mhz) or gigahertz (ghz)