Write a program with total change amount as an integer input that outputs the change using the fewest coins, one coin type per line. The coin types are dollars, quarters, dimes, nickels, and pennies. Use singular and plural coin names as appropriate, like 1 penny vs. 2 pennies.

Ex: If the input is:

0
or less, output:

no change
Ex: If the input is:

45
the output is:

1 quarter
2 dimes
Your program must define and call the following method. Positions 0-4 of coinVals should contain the number of dollars, quarters, dimes, nickels, and pennies, respectively.
public static void exactChange(int userTotal, int[] coinVals)

#include<stdio.h>

#define DOLLAR 100

#define QUARTER 25

#define DIME 10

#define NICKEL 5

#define PENNY 1

void calculatedChange(int userAmount,int coinValues[])

{

if (userAmount >=100)

{

coinValues[0]=userAmount/DOLLAR;

userAmount=userAmount-(100*coinValues[0]);

}

if (userAmount >=25)

{

coinValues[1]=userAmount/QUARTER;

userAmount=userAmount-(25*coinValues[1] );  

}

if (userAmount >=10)

{

coinValues[2]=userAmount/DIME;

userAmount=userAmount-(10*coinValues[2]);

}

if (userAmount >=5)

{  

coinValues[3]=userAmount/NICKEL;

userAmount=userAmount-(5*coinValues[3]);

}

if (userAmount >=1)

{

coinValues[4]=userAmount/PENNY;

userAmount=userAmount-coinValues[4];

}

}

int main() {

int amount;

printf("Enter the amount in cents :");

scanf("%d",&amount);

if(amount<1)

{

printf("No change..!");

}

else

{

int coinValues[5]={0,0,0,0,0};

calculatedChange(amount,coinValues);

if (coinValues[0]>0)

{

printf("%d Dollar",coinValues[0]);

if(coinValues[0]>1) printf("s");

}

if (coinValues[1]>0)

{

printf(" %d Quarter",coinValues[1]);

if(coinValues[1]>1) printf("s");

}

if (coinValues[2]>0)

{

printf(" %d Dime",coinValues[2]);

if(coinValues[2]>1) printf("s");

}

if (coinValues[3]>0)

{

printf(" %d Nickel",coinValues[3]);

if(coinValues[3]>1) printf("s");

}

if (coinValues[4]>0)

{

printf(" %d Penn",coinValues[4]);

if(coinValues[4]>1) printf("ies");

else printf("y");

}

}

}

Explanation:

answervpn;