Find the number of times a value appears in a list, and create a new list that contains the index positions where the value occurs in the list argument.

Program :

list_1=[]#take the empty list.

size=int(input("Enter the size of the list: "))#take the size of the list from the user

for x in range(size): #for loop which insert the elemnt on the list.

   list_1.append(int(input("Enter the "+str(x+1)+" element of the list: ")))#take the user input and insert the element.

element=int(input("Enter the element to be searched: "))#it take the elemnt to search.

loc=1#intialize the location value.

count=0

for x in list_1:#for loop to check the element.

   if(x==element): #check the element.

       print(loc,end=", ")#print the location of the element.

       count=count+1

   loc=loc+1

if(count==0):

   print("The element is not present on the list")#print when elemnt are not present.

Output:

Explanation:

false

explanation:

don't need road sign there is no cars

nope i prefer two because it is simpler, i don't like all the powers you get

explanation:

but that's my opinion