Prove that, for all $n \geq 1$, $|\set{s \in \bit^n : K(s) < n}| \leq 2^n-1$, i. e.\ there are at most $2^n-1$ binary strings of length $n$ that have Kolmogorov complexity strictly less than $n$.

answer is:

a). backstage view

explanation:

backstage view is the area where files and data about them is managed— creating, saving, printing, sending to others, inspecting for hidden metadata or personal information, and setting options. so in this way we can add many things to our document swiftly.

i hope you get the idea.