Consider a system that uses a 32-bit unique salt where users have a 4-digit number as a password (e. g. 6813). Eve wants to crack the accounts of two users, Alice and Bob. Eve performs an online attack, and is able to guess 1 password per second, though there is no lockout after guessing too many times. In the worst case, in seconds, how long will it take Eve to crack both Alice's and Bob's accounts?

Matlab question: use switch and anythe lottery game matches three different integer numbers between 1 and 10. winning depends on how many matching numbers are provided by a player. the player provides three different integers between 1 and 10.if there is a match of all 3 numbers, the winning $ 1000.if there is a match with 2 numbers, the winning $ 10.if there is a match of all with 1 numbers, the winning $ 1.with no match, the winning is $0.write a function lottery3 that checks three numbers provided by a player and determine the winning amount. if the user mistakenly enters same number twice/thrice and if that number matches one of the winning numbers, the code should count that number only once and display correct result. the player doesn’t have to guess the order of numbers.the input to the function lottery3 can have up to two input arguments. the first input argument is a row array numbers with 3 numbers. if the second argument input testcode is present, and is a row vector of 3 values, the function lottery3 uses the code in testcode as the three winning numbers (the test must be three different integer numbers between 1 and 10), else three different numbers will be automatically generated by testcode.the ouput should return the variable winnings and the three winning numbers in the row array winnumbers.hint: make use of the internal function any.restriction: the function must use switch-case statements to determine the winning.example #1: winning = lottery3( [1,2,1],[1,2,3])produceswinning =10example #2: [winning,winnumbers] = lottery3( [1,2,3])produceswinning =3winnumbers =8 5 3

Usually, when we sniff packets, we are only interested certain types of packets. we can do that by setting filters in sniffing. scapy’s filter use the bpf (berkeley packet filter) syntax; you can find the bpf manual from the internet. set the following filters and demonstrate your sniffer program again (each filter should be set separately): (a) capture only the icmp packet. (b) capture any tcp packet that comes from a particular ip and with a destination port number 23. (c) capture packets comes from or to go to a particular subnet. you can pick any subnet, such as 128.230.0.0/16; you should not pick the subnet that your vm is attached to.

We as humans write math expression in infix notation, e.g. 5 + 2 (the operators are written in-between the operands). in a computer’s language, however, it is preferred to have the operators on the right side of the operands, i.e. 5 2 +. for more complex expressions that include parenthesis and multiple operators, a compiler has to convert the expression into postfix first and then evaluate the resulting postfix.write a program that takes an “infix” expression as input, uses stacks to convert it into postfix expression, and finally evaluates it. it must support the following operations: + - / * ^ % (example infix expression: (7 - 3) / (2 + 2)postfix expression: 7 3 - 2 2 + /result: 1guidelines: 1. you will need to use stacks in three placesa. one for the parenthesis check [char stack]b. one during infix to postfix [char stack]c. one during evaluation [int stack]for a and b above, you can use same array and same push, pop method as both ofthem are char. but for evaluation you have int stack and you might consider to createanother push pop method to handle it. maybe push_int, pop_int, etc. or find otherstrategy to utilize existing push pop method2. you can create a function for obtaining operator priority. that function should take anoperator as input and return its priority as an integer. this function will you a lot andreduce repeated code3. during evaluation you will need to convert char into integer. example for single digit: char c = '5'; int x = c - '0';