Computers and Technology, 13.02.2020 23:00 Jasten

Information management examines the organizational resource of information and regulates its definitions, uses, value, and distribution ensuring it has the types of data/information required to function and grow effectively.

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Computers and Technology, 22.06.2019 05:20

Write a program called assignment3 (saved in a ﬁle assignment3.java) that computes the greatest common divisor of two given integers. one of the oldest numerical algorithms was described by the greek mathematician, euclid, in 300 b.c. it is a simple but very e↵ective algorithm that computes the greatest common divisor of two given integers. for instance, given integers 24 and 18, the greatest common divisor is 6, because 6 is the largest integer that divides evenly into both 24 and 18. we will denote the greatest common divisor of x and y as gcd(x, y). the algorithm is based on the clever idea that the gcd(x, y) = gcd(x ! y, y) if x > = y and gcd(x, y) = gcd(x, y ! x) if x < y. the algorithm consists of a series of steps (loop iterations) where the “larger” integer is replaced by the di↵erence of the larger and smaller integer. this continues until the two values are equal. that is then the gcd.

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Computers and Technology, 22.06.2019 11:30

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Computers and Technology, 23.06.2019 06:00

What machine listens for http requests to come in to a website’s domain? a. a router b. a browser c. a server d. a uniform resource locator

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Computers and Technology, 24.06.2019 11:20

Print "censored" if userinput contains the word "darn", else print userinput. end with newline. ex: if userinput is "that darn cat.", then output is: censoredex: if userinput is "dang, that was scary! ", then output is: dang, that was scary! note: if the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "program end never reached." the system doesn't print the test case that caused the reported message.#include #include using namespace std; int main() {string userinput; getline(cin, userinput); int ispresent = userinput.find("darn"); if (ispresent > 0){cout < < "censored" < < endl; /* your solution goes here */return 0; }

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