Areceiver requires 10nw as input power. if all the system losses add up to 50db, then how much power is required from the source.

Gain (dB)=10 log(O.P./I.P)

Also, the loss(dB) = -gain(dB) = 10 log(I.P/O.P)

which is, 50 = 10 log(I.P./10nW)

and hence, anti-log(5) = I.P/10 nW

And thus the power required by the source is antilog(5)*10nW = 1 mW

Note: Power required by the receiver is the O.P. and the power required from the source is the I.P.

Explanation:

Please check the answer.

answer; /// i do believe that the correct answer is (the area the player will see in the game screen)

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.