What does the following loop do? int[] a = {6, 1, 9, 5, 12, 3}; int len = a. length; int x = 0; for (int i = 1; i < len; i++)if (a[i] > a[x]) x = i; system. out. println(x); 1. finds the position of the largest value in a.2. sums the elements in a.3. finds the position of the smallest value in a.4. counts the elements in a.

Option 1: Finds the position of the largest value in a

Explanation:

Given the codes as follows:

       int[] a = {6, 1, 9, 5, 12, 3};        int len = a.length;        int x = 0;        for (int i = 1; i < len; i++)        {            if (a[i] > a[x])                x = i;        }        System.out.println(x);

The code is intended to find a largest value in the array, a. The logic is as follows:

Define a variable to hold an index where largest value positioned. At the first beginning, just presume the largest value is held at index zero, x = 0. (Line 3) Next, compare the value location in next index. If the value in the next index is larger, update the index-x to the next index value (Line 4 - 8). Please note the for-loop traverse the array starting from index 1. This is to enable the index-1 value can be compared with index-0 and then followed with index-2, index-3 etc. After completion of the for-loop, the final x value will be the index where the largest value is positioned.Print the position of the largest value (Line 10)

Ithink it’s c. 1 pm and 3 pm