Write a program that reads in ten numbers and displays the number of distinct numbers and the distinct numbers separated by exactly one space (i. e., if a number appears multiple times, it is displayed only once).

(hint: read a number and store it to an array if it is new. if the number is already in the array, ignore it.)

after the input, the array contains the distinct numbers in the order of their input.

The program to this question can be given as:

Program:

//import package.

import java.util.*;

public class Main //defining the class

{

public static void main(String[] args) //defining main method  

{

 Scanner ob = new Scanner(System.in); //creating scanner class object.

 int[] a = new int[10];//define array.  

 int number,counts= 0,i;//define variable.

 System.out.print("Enter numbers: "); //message.

 for (i = 0; i < 10; i++) //loop  

 {

 number=ob.nextInt();

 if (isDistinct(a,number))

 {

      a[counts] = number;//assign value in array

      counts++;// Increment count

 }

 }

 System.out.println("The distinct numbers is :" + counts);

 System.out.print("The distinct number are :");

 for (i = 0; i <a.length; i++)//loop

 {

 if (a[i] > 0)

 {

   System.out.print(" " +a[i]);//print array.    

 }

 }

 System.out.println();

}

public static boolean isDistinct(int[] array, int num)//defining method  

{

 for (int i = 0; i < array.length; i++)//loop for check number  

 {

 if (num == array[i]) //check condition

 {

      return false; //return value false.

 }

 }

 return true; //return value true

}

}

Output:

First time run:  

Enter ten numbers: 1 2 3 4 5 6 7 8 9 10

The number of distinct numbers is 10

The distinct numbers are 1 2 3 4 5 6 7 8 9 10

Second time run:

Enter numbers: 2 3 5 8 7 4 3 2 1 2

The distinct numbers is :7

The distinct number are : 2 3 5 8 7 4 1

Explanation:

The description of the above java code can be given as:

so much for the extra points :