Computers and Technology, 05.12.2019 22:31 kereshmeh
Consider the following rucursive descent parser: void a() { if( next_token == 'a' ) { lex(); if( next_token == 'a') { lex(); a(); lex(); c(); } else error(); } else if(next_token == 'b') { lex(); b(); lex(); c(); } else error(); }void b() { if( next_token == 'a' ) { lex(); if( next_token == 'b' ) { lex(); b(); } else error(); } else if ( next_token ! = 'b' ) { error(); }}void c() { if( next_token == 'c' ) { lex(); if( next_token == 'a' ) { lex(); if( next_token ! = 'b' ) { error(); } } else error(); } else error(); }which of the following strings will parse without an error? a. aabbcabcabb. aacabbbcabc. cab
Answers: 1
Computers and Technology, 23.06.2019 09:20
How to print: number is equal to: 1 and it is odd number number is equal to: 2 and it is even number number is equal to: 3 and it is odd number number is equal to: 4 and it is even number in the console using java using 1 if statement, 1 while loop, 1 else loop also using % to check odds and evens
Answers: 3
Computers and Technology, 23.06.2019 12:30
Animations and transitions are added from the
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Computers and Technology, 23.06.2019 13:30
Stops: using the information learned in this course, explain three things you will not do when driving. a. b. c. explain why you will not do these things when driving. starts: using the information learned in this course, explain three things you will do when driving. a. b. c. explain why you will do these particular things when driving. explain one thing you will stop doing as a passenger. explain one thing you will start doing as a passenger.
Answers: 3
Consider the following rucursive descent parser: void a() { if( next_token == 'a' ) { lex(); if( ne...
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